(3x^1/2)-(16x^1/4)-12=0

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Solution for (3x^1/2)-(16x^1/4)-12=0 equation: 


x in (-oo:+oo)

(3*x^1)/2-((16*x^1)/4)-12 = 0

(3*x)/2-4*x-12 = 0

-5/2*x-12 = 0 // + 12

-5/2*x = 12 // : -5/2

x = 12/(-5/2)

x = -24/5

x = -24/5

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